{"id":18090,"date":"2024-03-10T00:36:49","date_gmt":"2024-03-10T00:36:49","guid":{"rendered":"https:\/\/soicau5095.minhngocxoso.com\/?p=18090"},"modified":"2024-03-10T00:36:49","modified_gmt":"2024-03-10T00:36:49","slug":"bat-mi-cach-tinh-xac-suat-lo-de-chinh-xac-nhat","status":"publish","type":"post","link":"https:\/\/lotoxoso88.com\/bat-mi-cach-tinh-xac-suat-lo-de-chinh-xac-nhat\/","title":{"rendered":"b\u1eadt m\u00ed c\u00e1ch t\u00ednh x\u00e1c su\u1ea5t l\u00f4 \u0111\u1ec1 ch\u00ednh x\u00e1c nh\u1ea5t"},"content":{"rendered":"
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Nhi\u1ec1u ng\u01b0\u1eddi ch\u01a1i \u0111\u1ec1 ch\u1eafc ch\u1eafn l\u00e0 \u0111ang b\u0103n kho\u0103n v\u1ec1 vi\u1ec7c l\u00e0m sao d\u1ef1 \u0111o\u00e1n \u0111\u01b0\u1ee3c l\u00f4 c\u1ea7u ch\u00ednh x\u00e1c nh\u1ea5t . Soi c\u1ea7u c\u00f3 d\u1ec5 kh\u00f4ng ? D\u1ec5 hay kh\u00f4ng c\u00f2n tu\u1ef3 v\u00e0o 3 y\u1ebfu t\u1ed1 l\u00e0 t\u00ednh x\u00e1c su\u1ea5t, quy lu\u1eadt s\u1ed1 Pi v\u00e0 c\u1ea3m gi\u00e1c s\u1ed1. V\u00e0 v\u00ec v\u1eady, h\u00f4m nay ch\u00fang t\u00f4i g\u1eedi \u0111\u1ebfn c\u00e1c b\u1ea1n b\u00e0i vi\u1ebft v\u1ec1 ph\u01b0\u01a1ng ph\u00e1p t\u00ednh x\u00e1c su\u1ea5t trong l\u00f4 \u0111\u1ec1 \u0111\u1ec3 b\u1ea1n tham kh\u1ea3o c\u00e1ch \u0111\u00e1nh v\u00e0 c\u00e1ch ch\u01a1i v\u00ec kh\u00f4ng c\u00f3 g\u00ec l\u00e0 ch\u1eafc ch\u1eafn.<\/p>\n\n\n\n
M\u00ecnh kh\u00f4ng t\u00ednh l\u00e0 tr\u00fang 2 ph\u00e1t, hay 3 ph\u00e1t. M\u00e0 ch\u1ec9 t\u00ednh tr\u00fang l\u00f4.
\u0110\u00e1nh 1 con l\u00f4 \u0111\u1ec1 tr\u00fang x\u00e1c su\u1ea5t= 1 \u2013 (X\u00e1c su\u1ea5t t\u1ea1ch l\u00f4) = 1 \u2013 0,99^27 (quay 27 s\u1ed1 \u0111\u1ec1u t\u1ea1ch) = 23,7657%<\/p>\n\n\n\n
Kh\u00f4ng ph\u1ea3i t\u00ednh c\u1ee7a bi\u1ebft l\u00e0 1% r\u1ed3i.<\/p>\n\n\n\n
C\u00f3 hai tr\u01b0\u1eddng h\u1ee3p kh\u00f4ng tr\u00fang l\u00f4 xi\u00ean 2: L\u00e0 kh\u00f4ng v\u1ec1 c\u1ea3 hai con v\u00e0 ch\u1ec9 v\u1ec1 1 con.
X\u00e1c su\u1ea5t kh\u00f4ng v\u1ec1 c\u1ea3 hai con = 0,98^27 = 57,957%.
X\u00e1c su\u1ea5t ch\u1ec9 v\u1ec1 1 con: Tr\u01b0\u1eddng h\u1ee3p n\u00e0y c\u00f3 2 tr\u01b0\u1eddng h\u1ee3p l\u00e0 con th\u1ee9 nh\u1ea5t v\u1ec1 v\u00e0 con th\u1ee9 2 kh\u00f4ng v\u1ec1 v\u00e0 ng\u01b0\u1ee3c l\u1ea1i.
=> X\u00e1c su\u1ea5t ch\u1ec9 v\u1ec1 1 con = 2 * x\u00e1c su\u1ea5t tr\u00fang 1 l\u00f4 * x\u00e1c su\u1ea5t kh\u00f4ng tr\u00fang l\u00f4 = 2 * 23,7657% * 0,99^27 = 36,238%.
X\u00e1c su\u1ea5t kh\u00f4ng tr\u00fang l\u00f4 xi\u00ean 2 = X\u00e1c su\u1ea5t kh\u00f4ng v\u1ec1 c\u1ea3 2 con + x\u00e1c su\u1ea5t ch\u1ec9 v\u1ec1 1 con = 57,957% + 36,238% = 94,195%.
X\u00e1c su\u1ea5t tr\u00fang l\u00f4 xi\u00ean 2 = 100% \u2013 X\u00e1c su\u1ea5t kh\u00f4ng tr\u00fang = 100 \u2013 94,195% = 5,8%<\/p>\n\n\n\n
T\u01b0\u01a1ng t\u1ef1 v\u1edbi c\u00e1ch t\u00ednh l\u00f4 xi\u00ean 2, nh\u01b0ng tr\u01b0\u1eddng h\u1ee3p kh\u00f4ng tr\u00fang l\u00f4 xi\u00ean 3 nhi\u1ec1u h\u01a1n n\u00ean t\u00ednh l\u00e2u h\u01a1n. C\u00e1ch t\u00ednh t\u01b0\u01a1ng t\u1ef1 nh\u1ee9 l\u00f4 xi\u00ean 2.
X\u00e1c kh\u00f4ng tr\u00fang l\u00f4 xi\u00ean 3 = X\u00e1c su\u1ea5t kh\u00f4ng v\u1ec1 c\u1ea3 3 con + x\u00e1c su\u1ea5t ch\u1ec9 v\u1ec1 1 con + x\u00e1c su\u1ea5t ch\u1ec9 v\u1ec1 2 con = 0,97^27 + 3 * 23,7675% * 0,98^27 + 3 * 5,8% * 0,99^27 = 98,527%
=> X\u00e1c su\u1ea5t tr\u00fang l\u00f4 xi\u00ean 3 = 100% \u2013 98,527% = 1,473% ( d\u1ec5 h\u01a1n tr\u00fang \u0111\u1ec1 1 t\u00fd).<\/p>\n\n\n
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Gi\u1ea3 s\u1eed ta \u0111\u00e1nh L\u00d4 trong n ng\u00e0y li\u00ean ti\u1ebfp. H\u00e3y \u01b0\u1edbc l\u01b0\u1ee3ng n \u0111\u1ec3 x\u00e1c su\u1ea5t ta tr\u00fang 1 l\u1ea7n \u0111\u1ea1t g\u1ea7n 100%.
Gi\u1ea3i
G\u1ecdi A l\u00e0 bi\u1ebfn c\u1ed1 trong n ng\u00e0y, ta kh\u00f4ng tr\u00fang l\u1ea7n n\u00e0o.
G\u1ecdi B l\u00e0 bi\u1ebfn c\u1ed1 ta ch\u00fang \u00edt nh\u1ea5t 1 l\u1ea7n.
X\u00e1c su\u1ea5t \u0111\u1ec3 ta tr\u01b0\u1ee3t c\u1ea3 27 con l\u00f4 trong d\u00e0n l\u00f4 c\u1ee7a m\u1ed9t ng\u00e0y l\u00e0: 0,99^27. Do \u0111\u00f3:P(A) = 0,99^27n
P(B) = 1\u2212P(A) = 1\u22120,99^27n
P(B) > m \u21d4 0,99^27n < 1\u2212m \u21d4 n > log0,99(1\u2212m)\/27V\u1edbi m = 0,9999, ta c\u00f3: n > 33,9, t\u1ee9c l\u00e0 trong v\u00f2ng 34 ng\u00e0y th\u00ec x\u00e1c su\u1ea5t ta \u0111\u00e1nh tr\u00fang \u00edt nh\u1ea5t 1 l\u1ea7n l\u00e0 99,99%.<\/p>\n\n\n\n
Tr\u00ean \u0111\u00e2y l\u00e0 c\u00e1ch t\u00ednh x\u00e1c su\u1ea5t l\u00f4 \u0111\u1ec1 ch\u00ednh x\u00e1c nh\u1ea5t. C\u00e1c b\u1ea1n theo d\u00f5i website \u0111\u1ec3 c\u1eadp nh\u1eadp c\u00e1c ph\u01b0\u01a1ng ph\u00e1p m\u1edbi v\u00e0 t\u00ecm cho m\u00ecnh m\u1ed9t con s\u1ed1 \u0111\u1eb9p nh\u1ea5t trong ng\u00e0y. Ch\u00fac c\u00e1c b\u1ea1n may m\u1eafn<\/p>\n\n\n
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